Node Ring Connections
Posted: 22 Sep 2014 21:26
For discussion . . . . . .
Recently, I have been trying to get a Node system running, unfortunately, the ROMs that I am trying to use have a problem and won't let the MTX boot. However, as part of the effort to get a ring running, I have tried to work out how the nodes should be physically connected.
My "best guess" on how the ring would be cabled is on this page :
http://www.primrosebank.net/computers/m ... txnode.htm
Having read the page, Bill (Brendling) made a few observations on the subject of resistors. I have included some of Bill's comments below. Bill suggested that we open this conversation to a wider audience, hence this thread. Hopefully, it will stimulate further discussion and we can make a better "guess" on how the system was originally connected.
" . . . What I think is more likely is some resistors for impedance matching to the coax cable. I would expect:
A series resister between the TX pin on the 25-D connector and the centre of the "Data Out" coax connector.
A parallel resister from the "Data In" connector to ground.
The value of these resistors would be either 50 ohm or 75 ohm depending upon the impedance of the cable used.
The effect of these resisters would be to halve the voltage seen on the RX pin, but more importantly it would reduce the occurrence of signal reflections at the ends of the coax cables. This would be important particularly for longer cable lengths."
"A resistor from the signal pin to ground (as I describe for the RX pin) is often called a "terminator" or "terminating resistor". At the transmit end you can either have another resistor to ground and then a constant current drive, or (as in the case of the MTX serial port) a constant voltage drive and a series resistor."
"If I remember the chip specs correctly, the TX line drives at +/-10V, while the RX line only requires +/-3V. More of a concern is the current consumption. If 75 ohm coax is used then each transmitter would see 150 ohms. and would have to supply 67 mA. With 50 ohm coax it is worse, the transmitter is driving 100 ohms and has to supply 100 mA."
Anyone else care to comment?
regards
Dave
Recently, I have been trying to get a Node system running, unfortunately, the ROMs that I am trying to use have a problem and won't let the MTX boot. However, as part of the effort to get a ring running, I have tried to work out how the nodes should be physically connected.
My "best guess" on how the ring would be cabled is on this page :
http://www.primrosebank.net/computers/m ... txnode.htm
Having read the page, Bill (Brendling) made a few observations on the subject of resistors. I have included some of Bill's comments below. Bill suggested that we open this conversation to a wider audience, hence this thread. Hopefully, it will stimulate further discussion and we can make a better "guess" on how the system was originally connected.
" . . . What I think is more likely is some resistors for impedance matching to the coax cable. I would expect:
A series resister between the TX pin on the 25-D connector and the centre of the "Data Out" coax connector.
A parallel resister from the "Data In" connector to ground.
The value of these resistors would be either 50 ohm or 75 ohm depending upon the impedance of the cable used.
The effect of these resisters would be to halve the voltage seen on the RX pin, but more importantly it would reduce the occurrence of signal reflections at the ends of the coax cables. This would be important particularly for longer cable lengths."
"A resistor from the signal pin to ground (as I describe for the RX pin) is often called a "terminator" or "terminating resistor". At the transmit end you can either have another resistor to ground and then a constant current drive, or (as in the case of the MTX serial port) a constant voltage drive and a series resistor."
"If I remember the chip specs correctly, the TX line drives at +/-10V, while the RX line only requires +/-3V. More of a concern is the current consumption. If 75 ohm coax is used then each transmitter would see 150 ohms. and would have to supply 67 mA. With 50 ohm coax it is worse, the transmitter is driving 100 ohms and has to supply 100 mA."
Anyone else care to comment?
regards
Dave